Aqueous ferric chloride (FeCl3) reacts with aqueous sodium hydroxide (NaOH) khổng lồ produce ferric hydroxide ( Fe(OH)3 ) và sodium chloride (NaCl). So, yellow-brown màu sắc solution will turn into a brown màu sắc precipitate. Màu sắc changes, precipitating, balanced reaction, ionic equation of FeCl2 + NaOH reaction are discussed in this tutorial.Bạn sẽ xem: Fecl3 + naoh → fe(oh)3 + nacl
Aqueous ferric chloride & aqueous sodium hydroxide reaction
Ferric chloride ( Iron(III) chloride ) is a soluble inorganic compound in water và form a yellow-brown solution.
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Sodium hydroxide is a strong alkaline colorless solution & readily gives hydroxyl ions (OH-).
What are the products when aqueous FeCl3 reacts with aqueous NaOH
When we showroom aqueous NaOH solution to lớn aqueous FeCl3 solution, brown color precipitate is formed. This precipitate is ferric hydroxide ( Fe(OH)3 ).
FeCl3 + NaOH = Fe(OH)3 + NaCl
Above mentioned reaction is not a balanced chemical reaction. So, we need khổng lồ balance this reaction & we will bởi it next section.
How khổng lồ balance FeCl3 & NaOH reaction?
This reaction is a not a redox reaction. Therefore by observing number of atoms in right side and left side, we can balance the reaction in few seconds. This method is a trial và error method. But it is so easy for like this simple equation.
Balanced reaction and stoichiometry of FeCl3 và NaOHFeCl3 + 3NaOH = Fe(OH)3 + 3NaCl
According to the stoichiometry of the reaction, 1 mol of FeCl3 reacts with 3 mol of NaOH & produce 1 mol of Fe(OH)3 và 3 mol of NaCl.
Balanced reaction of FeCl2 và NaOH with physical statesFeCl3(aq) + 3NaOH(aq) = Fe(OH)3(s) + 3NaCl(aq)
FeCl3 is soluble in water. Therefore, it exists as an aqueous solution & NaOH also exists as a solution. But, solubility of Fe(OH)3 is poor in water. Hence it deposits as a precipitate at the bottom of the reaction. NaCl is very much soluble in water và exists as an aqueous solution.
Let's solve a problem about FeCl3 + NaOH reaction
There are two aqueous solutions. In one solution, there is 0.1 mol dm-3 FeCl3 0.1 dm3 và other aqueous solution is 0.1 mol dm-3 NaOH2 0.1 dm3. When, these two solutions are mixed with each other, how much grams are precipitated as Fe(OH)3?
Answer: First, you have khổng lồ find mixed amounts of NaOH & FeCl3.Mixed NaOH amount = 0.01 mol Mixed amount of FeCl2 = 0.01 mol
To react with 0.01 mol FeCl3, 0.03 mol of NaOH is required according khổng lồ the stoichiometric equation. But, there is only, 0.01 mol of NaOH. Therefore, NaOH is the limited reagent.Produced FeCl3 amount = 0.0033 mol Prodyced Fe(OH)3 mass = 0.54 g
Assumption: Amount of Fe(OH)3 in the aqueous phase is negligible compared lớn amount in the precipitate.
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Fe(OH)2 is not soluble in excess NaOH or aqueous ammonia solution. So brown colour precipitate will remain in the solution.Related TutorialsFeCl2 + NaOH reaction Reaction of cold và hot NaOH + Cl2 Solubility of metal hydroxides